A 0.5 M solution of hydrochloric acid (HCl) is mixed with a 0.5 M solution of sodium hydroxide (NaOH). Write the balanced chemical equation for the reaction and determine the products formed.
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When a 0.5 M solution of hydrochloric acid (HCl) is mixed with a 0.5 M solution of sodium hydroxide (NaOH), they undergo a neutralization reaction. The balanced chemical equation for this reaction is:
HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)
In words, hydrochloric acid reacts with sodium hydroxide to produce sodium chloride (NaCl) and water (H2O).
Explanation:
This reaction is a classic example of acid-base neutralization, where an acid and a base react to form a salt and water.
HCl + NaOH –> NaCl + H2O
The given reaction is between HCl (a strong acid) and NaOH (a strong base). The reaction of an acid and base always results into a salt with water as by-product of the reaction. So the products formed will be NaCl (a salt) and H2O (water).
HCl + NaOH –> NaCl + H2O
The given reaction is between HCl (a strong acid) and NaOH (a strong base). The reaction of an acid and base always results into a salt with water as by-product of the reaction. So the products formed will be NaCl (a salt) and H2O (water).
HCl + NaOH –> NaCl + H2O
The given reaction is between HCl (a strong acid) and NaOH (a strong base). The reaction of an acid and base always results into a salt with water as by-product of the reaction. So the products formed will be NaCl (a salt) and H2O (water).