In how many different ways, 2 Mathematics, 4 Economics and 6 History books can be selected from 7 Mathematics, 10 Economics and 9 History books?
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To solve this problem, we can use the combination formula, which is:
C(n, k) = n! / (k! * (n – k)!)
Where n is the total number of items to choose from, and k is the number of items to choose.
In this case, we have 7 Mathematics books, 10 Economics books, and 9 History books to choose from. We need to select 2 Mathematics books, 4 Economics books, and 6 History books.
So, the total number of ways to select the books is:
C(7, 2) * C(10, 4) * C(9, 6) = (7! / (2! * (7 – 2)!)) * (10! / (4! * (10 – 4)!)) * (9! / (6! * (9 – 6)!))
This simplifies to:
(7 * 6 / (2 * 1)) * (10 * 9 * 87 / (4 * 3 * 2 * 1)) * (9 * 8 * 7 * 6 * 5 * 4 / (6 * 5 * 4 * 3 * 2 * 1))
This simplifies further to:
21 * 1260 * 60480 = 1,764,480
Therefore, there are 1,764,480 different ways to select 2 Mathematics books, 4 Economics books, and 6 History books from the given sets of books.