Home/the length of a rectangle is increased by 60%. by what percent would the width have to be decreased so as to maintain the same area?
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Aptitude on Area: – The length of a rectangle is increased by 60%. By what percent would the width have to be decreased so as to maintain the same area?
Area1 = Area2 L*W = 1.6*L*Wnew Wnew = W/1.6 = 0.625 W Width must be decreased by 100-62.5 = 37.5%
Area1 = Area2
L*W = 1.6*L*Wnew
Wnew = W/1.6 = 0.625 W
Width must be decreased by 100-62.5 = 37.5%
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