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Home/aptitude

Mains Answer Writing Latest Questions

LOHIT MISHRA
  • 0
LOHIT MISHRABegginer
Asked: July 16, 2024In:
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A man is looking at a photograph of someone. His friend asks who it is. The man replies: “Brothers and sisters, I have none. But that man’s father is my father’s son.” Who is in the photograph?

aptitudemathsquestion
  1. mhk saini
    mhk saini Learner

    His son Man have no siblings and he yalked about father son that was him. He was the only son of that man . The man in photograph is his father

    His son

    Man have no siblings and he yalked about father son that was him. He was the only son of that man . The man in photograph is his father

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LOHIT MISHRA
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LOHIT MISHRABegginer
Asked: July 16, 2024In:
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In a certain code language, the word “PROBLEM” is written as “ROPELBM”. How will the word “DIFFICULT” be written in that same code?

aptitudemathquestion
  1. mhk saini
    mhk saini Learner

    The word PROBLEM is rearrange in ROPELBM IN THIS FORMAT BY Arranging places with their neighbours letters P-R R-O O-P B-E L-L E-B M-M Applying same to difficult D-I I-D F-F F-I I-F C-C U-C L-L T-T  

    The word PROBLEM is rearrange in ROPELBM IN THIS FORMAT

    BY Arranging places with their neighbours letters

    P-R

    R-O

    O-P

    B-E

    L-L

    E-B

    M-M

    Applying same to difficult

    D-I

    I-D

    F-F

    F-I

    I-F

    C-C

    U-C

    L-L

    T-T

     

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Nivedita Tiwari
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Nivedita TiwariBegginer
Asked: July 20, 2024In:
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A tank has three pipes: A, B, and C. Pipe A can fill the tank in 10 hours, Pipe B can fill the tank in 15 hours, and Pipe C can empty the tank in 20 hours. If all three ...

aptitudemathsquestion
  1. SAMIRAN PAL
    SAMIRAN PAL Begginer

    Calculate Individual Rates: Pipe A fills the tank in 10 hours:  110\frac{1}{10}​ of the tank per hour. Pipe B fills the tank in 15 hours:  115\frac{1}{15}​ of the tank per hour. Pipe C empties the tank in 20 hours:  120\frac{1}{20} of the tank per hour. Find the Combined Rate: Combined filling rateRead more

    Calculate Individual Rates:

    1. Pipe A fills the tank in 10 hours:  110\frac{1}{10}​ of the tank per hour.
    2. Pipe B fills the tank in 15 hours:  115\frac{1}{15}​ of the tank per hour.
    3. Pipe C empties the tank in 20 hours:  120\frac{1}{20} of the tank per hour.

    Find the Combined Rate:

    • Combined filling rate of A and B:   110+115=530=16\frac{1}{10} + \frac{1}{15} = \frac{5}{30} = \frac{1}{6} ​
    • Subtract the emptying rate of C:    16−120=760\frac{1}{6} – \frac{1}{20} = \frac{7}{60} ​

    Calculate the Time to Fill the Tank:

    • The combined rate is 760\frac{7}{60}​ of the tank per hour.
    • Time to fill the tank: 607\frac{60}{7}​ hours, which is approximately 8 hours and 34 minutes

    Answer: It will take approximately 8 hours and 34 minutes to fill the tank.

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Regina98
  • 1
Regina98Begginer
Asked: July 31, 2024In: ,
  • 1

What is the use of  aptitude test in competitive exams?

aptitudebankingcompetitive exams
  1. Arundhati Dutta
    Arundhati Dutta Begginer

    Aptitude tests are commonly used in competitive exams for several reasons: Assessing Basic Skills : They measure fundamental skills such as numerical ability, logical reasoning, and verbal proficiency, which are essential for academic and professional fields. Standardization : These tests provide aRead more

    Aptitude tests are commonly used in competitive exams for several reasons:

    1. Assessing Basic Skills : They measure fundamental skills such as numerical ability, logical reasoning, and verbal proficiency, which are essential for academic and professional fields.
    2. Standardization : These tests provide a standardized method to evaluate the abilities of all candidates, ensuring a fair comparison based on a common set of criteria.
    3. Predicting Success : Aptitude tests are designed to predict a candidate’s ability to succeed in future tasks, courses, or job roles. High scores often correlate with better performance in the relevant field.
    4. Identifying Potential : They help in identifying candidates with the potential to excel in specific areas, even if they lack prior knowledge or experience in those areas.
    5. Efficiency : Aptitude tests can quickly and efficiently screen large numbers of candidates, making the selection process more manageable.
    6. Eliminating Bias : By focusing on objective skills rather than subjective factors, aptitude tests help reduce biases that might arise from interviews or other subjective evaluation methods.
    7. Diagnostic Tool : These tests can diagnose strengths and weaknesses, helping candidates understand areas where they need improvement and aiding educators in tailoring their instruction accordingly.
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Avni Kolapkar
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Avni KolapkarBegginer
Asked: August 8, 2024In:
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aptitude
  1. Monisha S
    Monisha S

    Total Distance the train needs to cover, 120 m+ 130 m (platform length) = 250 m. Speed of the train is, 120 m/ 12 sec = 10 m/sec. (s=D/t) Now, to cover 250 meters at 10 meters per second, the train take, 250 m / 10 m/sec = 25 sec. Therefore, It will take 25 seconds to pass the platform.

    Total Distance the train needs to cover,

    120 m+ 130 m (platform length) = 250 m.

    Speed of the train is,

    120 m/ 12 sec = 10 m/sec. (s=D/t)

    Now, to cover 250 meters at 10 meters per second, the train take,

    250 m / 10 m/sec = 25 sec.

    Therefore,

    It will take 25 seconds to pass the platform.

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Anonymous
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Anonymous
Asked: July 16, 2024In:
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Ratio of ages of A and B, 4 years later is 8:9 respectively. If average of present ages of A & B is 47 years, then find difference in present ages of A & B.

age problemaptitudemaths problemquestion
  1. ANOOP RAJESH MUNDAYOOR
    ANOOP RAJESH MUNDAYOOR Begginer
    This answer was edited.

    This is an aptitude based question.Let us assume that x is the age of A and y be the age of B.So four years later their age will become  x+4 and y+4.It is given that the ratio of x+4 and y+4 is  8:9.By this we get to know that the age of B is more than age of A. Let's  take m as the common variableRead more

    This is an aptitude based question.Let us assume that x is the age of A and y be the age of B.So four years later their age will become  x+4 and y+4.It is given that the ratio of x+4 and y+4 is  8:9.By this we get to know that the age of B is more than age of A. Let’s  take m as the common variable for the ratio.We need to take m because 8:9 might be formed by dividing into lowest term.But one thing that can be determined is that after four years age of A will be in multiple of 8 and age of B will be in multiple of 9

    x+4=8m and y+4=9m

    Subtracting 4 on both sides for both the equations

    we get x=8m-4 and y=9m-4.—–Eq.1

    Now we have been given that average of age of A and B is 47 years.So

    (x+y)/2=47

    Multiplying by 2 on both sides we can get

    x+y=94——-Eq.2

    Now we can substitute the values of x and y obtained in equation 1 into equation 2.

    So. 8m-4+9m-4=94

    Which gives 17m-8=94

    On adding 8 on both sides we get 17m=102

    So we get the value of m as 6 since 102/17=6.

    Substituting m in equation we can get value of x and y

    x=8m-4=8×6-4=48-4=44

    y=9m-4=9×6-4=54-4=50

    So we get the present age of A as 44 and B as 50.So the difference in their age is 50-44=6.Hence B is 6 years elder than A

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LOHIT MISHRA
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LOHIT MISHRABegginer
Asked: July 16, 2024In:
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A tank has two pipes. Pipe A can fill the tank in 6 hours, and Pipe B can fill the tank in 8 hours. There is also a third pipe, Pipe C, which can empty the tank in 12 hours. ...

aptitudemathquestion
  1. ANOOP RAJESH MUNDAYOOR
    ANOOP RAJESH MUNDAYOOR Begginer

    The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative. It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(SinceRead more

    The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.

    It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)

    On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.

    Tank A takes 6 hours So it will fill 1/6th  of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.

    So after one hour:-

    1/6+1/8-1/12=

    (We will take L.C.M for 6,8,12 which is 24)

    (4+3-2)/24=5/24.

    So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume  that capacity of tank is 24 litres and 5 litre is increased every hour.

    So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.

    So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes

    The final answer is 4 hours and 48 minutes.

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Shubham Dhongadi
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Shubham DhongadiBegginer
Asked: July 18, 2024In: ,
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aptitudecreativitycritical thinking
  1. Vaishnavi Gupta
    Vaishnavi Gupta Begginer

    Hii shubham, I just solve this question and I pleased to share my answer with you... So here's the answer of your question:- You can measure exactly 4 gallons of water using the 3-gallon jug and the 5-gallon jug by following these steps: 1. Fill the 5-gallon jug completely. 2. Pour water from the 5-Read more

    Hii shubham, I just solve this question and I pleased to share my answer with you…

    So here’s the answer of your question:-

    You can measure exactly 4 gallons of water using the 3-gallon jug and the 5-gallon jug by following these steps:

    1. Fill the 5-gallon jug completely.
    2. Pour water from the 5-gallon jug into the 3-gallon jug until the 3-gallon jug is full. This leaves you with 2 gallons in the 5-gallon jug.
    3. Empty the 3-gallon jug.
    4. Pour the 2 gallons from the 5 -gallon jug into the 3-gallon jug.
    5. Fill the 5 -gallon jug completely again.
    6. Pour water from the 5 -Gallon jug into the 3-gallon jug until the 3-gallon jug is full. Since the 3-gallon jug already has 2 gallons in it, you can only add 1 more gallon from the 5 -gallon jug.

    Now, you have exactly 4 gallons left in the 5-gallon jug.

    Hope you understand this well and in case of any query I resolve it for you for better understanding.

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Kartheek Jegan Kuberi Dhamodharan
  • 1
Kartheek Jegan Kuberi DhamodharanBegginer
Asked: July 19, 2024In:
  • 1

aptitudecompetitive examsupsc
  1. Deepansh Pandey
    Deepansh Pandey Learner

    Find dimensions of the smaller plots: Since each smaller plot has an area of 120 square meters120 \text{ square meters}120 square meters, we need to find pairs of integers (a,b)(a, b)(a,b) such that a×b=120a \times b = 120a×b=120. The factors of 120 and their corresponding pairs are: 1×120=1202×60=1Read more

    1. Find dimensions of the smaller plots:
      • Since each smaller plot has an area of 120 square meters120 \text{ square meters}120 square meters, we need to find pairs of integers (a,b)(a, b)(a,b) such that a×b=120a \times b = 120a×b=120.

      The factors of 120 and their corresponding pairs are:

      1×120=1202×60=1203×40=1204×30=1205×24=1206×20=1208×15=12010×12=12012×10=12015×8=12020×6=12024×5=12030×4=12040×3=12060×2=120120×1=120\begin{aligned} 1 \times 120 &= 120 \\ 2 \times 60 &= 120 \\ 3 \times 40 &= 120 \\ 4 \times 30 &= 120 \\ 5 \times 24 &= 120 \\ 6 \times 20 &= 120 \\ 8 \times 15 &= 120 \\ 10 \times 12 &= 120 \\ 12 \times 10 &= 120 \\ 15 \times 8 &= 120 \\ 20 \times 6 &= 120 \\ 24 \times 5 &= 120 \\ 30 \times 4 &= 120 \\ 40 \times 3 &= 120 \\ 60 \times 2 &= 120 \\ 120 \times 1 &= 120 \\ \end{aligned}1×1202×603×404×305×246×208×1510×1212×1015×820×624×530×440×360×2120×1​=120=120=120=120=120=120=120=120=120=120=120=120=120=120=120=120​

    2. Check compatibility with the field dimensions:
      • We need to check if the field of 60 meters by 40 meters can be divided into smaller plots of dimensions a×ba \times ba×b.

      To fit the dimensions into the field exactly, the length and width of the field (60 meters and 40 meters) must be divisible by the dimensions of the plot.

    3. Filter valid plot dimensions:
      • For each pair (a,b)(a, b)(a,b), check if both 60 is divisible by aaa and 40 is divisible by bbb, or vice versa.

      Valid pairs:

      (a,b)=(10,12)(since 60÷10=6 and 40÷12=3.333, not valid)(a,b)=(12,10)(since 60÷12=5 and 40÷10=4, valid)(a,b)=(20,6)(since 60÷20=3 and 40÷6=6.666, not valid)(a,b)=(6,20)(since 60÷6=10 and 40÷20=2, valid)(a,b)=(15,8)(since 60÷15=4 and 40÷8=5, valid)(a,b)=(8,15)(since 60÷8=7.5 and 40÷15=2.666, not valid)(a,b)=(30,4)(since 60÷30=2 and 40÷4=10, valid)(a,b)=(4,30)(since 60÷4=15 and 40÷30=1.333, not valid)\begin{aligned} (a, b) &= (10, 12) & \text{(since } 60 \div 10 = 6 \text{ and } 40 \div 12 = 3.333 \text{, not valid)} \\ (a, b) &= (12, 10) & \text{(since } 60 \div 12 = 5 \text{ and } 40 \div 10 = 4 \text{, valid)} \\ (a, b) &= (20, 6) & \text{(since } 60 \div 20 = 3 \text{ and } 40 \div 6 = 6.666 \text{, not valid)} \\ (a, b) &= (6, 20) & \text{(since } 60 \div 6 = 10 \text{ and } 40 \div 20 = 2 \text{, valid)} \\ (a, b) &= (15, 8) & \text{(since } 60 \div 15 = 4 \text{ and } 40 \div 8 = 5 \text{, valid)} \\ (a, b) &= (8, 15) & \text{(since } 60 \div 8 = 7.5 \text{ and } 40 \div 15 = 2.666 \text{, not valid)} \\ (a, b) &= (30, 4) & \text{(since } 60 \div 30 = 2 \text{ and } 40 \div 4 = 10 \text{, valid)} \\ (a, b) &= (4, 30) & \text{(since } 60 \div 4 = 15 \text{ and } 40 \div 30 = 1.333 \text{, not valid)} \\ \end{aligned}(a,b)(a,b)(a,b)(a,b)(a,b)(a,b)(a,b)(a,b)​=(10,12)=(12,10)=(20,6)=(6,20)=(15,8)=(8,15)=(30,4)=(4,30)​(since 60÷10=6 and 40÷12=3.333, not valid)(since 60÷12=5 and 40÷10=4, valid)(since 60÷20=3 and 40÷6=6.666, not valid)(since 60÷6=10 and 40÷20=2, valid)(since 60÷15=4 and 40÷8=5, valid)(since 60÷8=7.5 and 40÷15=2.666, not valid)(since 60÷30=2 and 40÷4=10, valid)(since 60÷4=15 and 40÷30=1.333, not valid)​So, valid pairs that fit exactly into the 60 by 40 field are:

      • (12,10)(12, 10)(12,10)
      • (6,20)(6, 20)(6,20)
      • (15,8)(15, 8)(15,8)
      • (30,4)(30, 4)(30,4)
    4. Counting the number of ways:
      • There are four distinct pairs of dimensions that can be used to divide the field into smaller plots with integer dimensions.

    Thus, there are 4\boxed{4}4​ different ways the farmer can divide the field into smaller plots of 120 square meters each with integer dimensions.

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Avni Kolapkar
  • 0
Avni KolapkarBegginer
Asked: August 8, 2024In:
  • 0

aptitude
  1. Anu Madal
    Anu Madal Begginer

    A train 120m long passes a pole in 12 seconds. here, distance travelled by train=length of train= 120m time taken by train= 12 seconds then speed of train=distance travelled by train/time taken by train speed of train= 120m/12sec =10 m/sec when train passes a 130 m long platform, distance travelledRead more

    A train 120m long passes a pole in 12 seconds.

    here, distance travelled by train=length of train= 120m

    time taken by train= 12 seconds

    then speed of train=distance travelled by train/time taken by train

    speed of train= 120m/12sec =10 m/sec

    when train passes a 130 m long platform,

    distance travelled by train= length of train + length of platform=120+130=250 m

    time taken by train to pass 130 m long platform=distance covered by train / speed of train

    time taken by  the train= 250 / 10= 25 seconds

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