A tank has two pipes. Pipe A can fill the tank in 6 hours, and Pipe B can fill the tank in 8 hours. There is also a third pipe, Pipe C, which can empty the tank in 12 hours. If all three pipes are open, how long will it take to fill the tank?
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The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
On adding the work done by all three pipes in one hour,we can get the amount of water filled in tank in one hour.
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.