A tank has two pipes. Pipe A can fill the tank in 6 hours, and Pipe B can fill the tank in 8 hours. There is also a third pipe, Pipe C, which can empty the tank in 12 hours. ...
The word PROBLEM is rearrange in ROPELBM IN THIS FORMAT BY Arranging places with their neighbours letters P-R R-O O-P B-E L-L E-B M-M Applying same to difficult D-I I-D F-F F-I I-F C-C U-C L-L T-T
The word PROBLEM is rearrange in ROPELBM IN THIS FORMAT
BY Arranging places with their neighbours letters
P-R
R-O
O-P
B-E
L-L
E-B
M-M
Applying same to difficult
D-I
I-D
F-F
F-I
I-F
C-C
U-C
L-L
T-T
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The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative. It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(SinceRead more
The point to be noted is that pipe A and B are used for filling the tank whereas pipe C empties the water.So we will take the time taken by pipe C in negative.
It has been in the question that pipe A fills the tank in 6hours and pipe B fills the tank in 8 hour.Pipe C fills the tank in -12hours(Since it empties the tank in 12 hours)
Tank A takes 6 hours So it will fill 1/6th of tank in 1 hour.Similarly Tank B will fill 1/8th of tank in 1 hour whereas Tank B will empty 1/12th of tank.
So after one hour:-
1/6+1/8-1/12=
(We will take L.C.M for 6,8,12 which is 24)
(4+3-2)/24=5/24.
So after one hour 5/24th of the tank will be filled. Since it is in the fraction 5/24, let us assume that capacity of tank is 24 litres and 5 litre is increased every hour.
So within 4 hours 20 litres will be filled into the tank.Time taken for the remaining 4 litres will be 4/5×60(we Multiply be 60 to convert into minutes).So it will take 48 minutes.
So the whole tank will get filled in 4 hour and 48 minutes or 60×4+48=288 minutes
The final answer is 4 hours and 48 minutes.
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