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The simple interest on a sum of money at 5% per annum for 3 years is $150. What is the principal amount?
To find the principal amount, we need to use the formula for simple interest: Principal = (Interest / Rate) x Time Given, I = $150, rate = 5% per year time = 3 yrs Therefore, Principal amount = (150 / 5) x 3 = (30) x 3 = 90 Therefore, the principal amount is $90.
To find the principal amount, we need to use the formula for simple interest:
Principal = (Interest / Rate) x Time
Given,
I = $150,
rate = 5% per year
time = 3 yrs
Therefore,
Principal amount = (150 / 5) x 3
= (30) x 3
= 90
Therefore, the principal amount is $90.
A train 120 meters long passes a pole in 12 seconds. How long will it take to pass a platform 130 meters long?
Total Distance the train needs to cover, 120 m+ 130 m (platform length) = 250 m. Speed of the train is, 120 m/ 12 sec = 10 m/sec. (s=D/t) Now, to cover 250 meters at 10 meters per second, the train take, 250 m / 10 m/sec = 25 sec. Therefore, It will take 25 seconds to pass the platform.
Total Distance the train needs to cover,
120 m+ 130 m (platform length) = 250 m.
Speed of the train is,
120 m/ 12 sec = 10 m/sec. (s=D/t)
Now, to cover 250 meters at 10 meters per second, the train take,
250 m / 10 m/sec = 25 sec.
Therefore,
It will take 25 seconds to pass the platform.
See lessA train 120 meters long passes a pole in 12 seconds. How long will it take to pass a platform 130 meters long?
Total Distance the train needs to cover, 120 m+ 130 m (platform length) = 250 m. Speed of the train is, 120 m/ 12 sec = 10 m/sec. (s=D/t) Now, to cover 250 meters at 10 meters per second, the train take, 250 m / 10 m/sec = 25 sec. Therefore, It will take 25 seconds to pass the platform.
Total Distance the train needs to cover,
120 m+ 130 m (platform length) = 250 m.
Speed of the train is,
120 m/ 12 sec = 10 m/sec. (s=D/t)
Now, to cover 250 meters at 10 meters per second, the train take,
250 m / 10 m/sec = 25 sec.
Therefore,
It will take 25 seconds to pass the platform.
See less