आरोही आँकड़ों का माध्य:

$\frac{57+110+112+114+x+118+120+y}{8}=108.5\backslash frac\{57\; +\; 110\; +\; 112\; +\; 114\; +\; x\; +\; 118\; +\; 120\; +\; y\}\{8\}\; =\; 108.5$857+110+112+114+x+118+120+y​=108.5

इससे,

$योग=8\times 108.5=868\backslash text\{योग\}\; =\; 8\; \backslash times\; 108.5\; =\; 868$योग=8×108.5=868

तो,

$57+110+112+114+x+118+120+y=86857\; +\; 110\; +\; 112\; +\; 114\; +\; x\; +\; 118\; +\; 120\; +\; y\; =\; 868$57+110+112+114+x+118+120+y=868

जिससे,

$x+y=868-611=257(611 = 57 + 110 + 112 + 114 + 118 + 120)x\; +\; y\; =\; 868\; –\; 611\; =\; 257\; \backslash quad\; \backslash text\{(611\; =\; 57\; +\; 110\; +\; 112\; +\; 114\; +\; 118\; +\; 120)\}$x+y=868−611=257(611 = 57 + 110 + 112 + 114 + 118 + 120)

अब, माध्यिका $114.5114.5$114.5 है, जिसका अर्थ है $xx$x और $yy$y का औसत $114.5114.5$114.5 है। इसलिए,

$\frac{x+y}{2}=114.5\Rightarrow x+y=229\backslash frac\{x\; +\; y\}\{2\}\; =\; 114.5\; \backslash Rightarrow\; x\; +\; y\; =\; 229$2x+y​=114.5⇒x+y=229

अतः $yx=257-229=28yx\; =\; 257\; –\; 229\; =\; 28$yx=257−229=28।

इसलिए, $yxyx$yx का मान 28 होगा।

छात्र के प्राप्तांक:

• हिंदी: $120\times 0.40=48120\; \backslash times\; 0.40\; =\; 48$120×0.40=48
• अंग्रेजी: $140\times 0.55=77140\; \backslash times\; 0.55\; =\; 77$140×0.55=77
• गणित: $100\times 0.45=45100\; \backslash times\; 0.45\; =\; 45$100×0.45=45

संयुक्त अंक:

$48+77+45=17048\; +\; 77\; +\; 45\; =\; 170$48+77+45=170

कुल अंक:

$120+140+100+180=540120\; +\; 140\; +\; 100\; +\; 180\; =\; 540$120+140+100+180=540

60% का लक्ष्य:

$0.60\times 540=3240.60\; \backslash times\; 540\; =\; 324$0.60×540=324

विज्ञान में अंक:

$x+170=324\Rightarrow x=154x\; +\; 170\; =\; 324\; \backslash Rightarrow\; x\; =\; 154$x+170=324⇒x=154

इसलिए, छात्र को विज्ञान में 154 अंक प्राप्त करने होंगे।

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