To determine the current age of the son, let’s denote his age by $xx$. According to the problem, the man is 24 years older than his son, so the man’s current age is $x+24x\; +\; 24$.

In two years, the son’s age will be $x+2x\; +\; 2$, and the man’s age will be $(x+24)+2=x+26(x\; +\; 24)\; +\; 2\; =\; x\; +\; 26$. The problem states that in two years, the man will be twice as old as his son. Therefore, we set up the following equation based on this information:

$x+26=2(x+2)$

To solve for $xx$, first simplify the equation:

$x+26=2x+4$

Next, isolate $xx$ by subtracting $xx$ from both sides:

$26=x+4$

Subtract 4 from both sides to solve for $xx$:

$22=x$

Thus, the current age of the son is 22 years old. This solution matches the conditions given in the problem: the man, who is 46 years old (22 + 24), will indeed be twice as old as his son in two years, as $46+2=4846\; +\; 2\; =\; 48$ and $22+2=2422\; +\; 2\; =\; 24$, and $48=2\times 2448\; =\; 2\; \backslash times\; 24$.

Therefore, the current age of the son is $\boxed{{\displaystyle 22}}\backslash boxed\{22\}$​.